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Mar 26, 2020 at 4:59 comment added Acccumulation @Oddthinking BTW, there's an approximation for this sort of situation of e^(-pn). Here, given your numbers, this give e^(-200*0.0116) = 0.0982735856 , or 9.8% chance that a flight won't have any infected.
Mar 26, 2020 at 3:40 comment added days of love iff good genes @Oddthinking: some more reading on this irishtimes.com/life-and-style/travel/… By the time the flight disembarks, there might be 10 people seeded by that one, if the flight was full.
Mar 26, 2020 at 2:25 comment added Oddthinking DeSantis's claim of every single flight seems extreme. Back of envelope: NY has 30,811 confirmed cases (and counting). Assume that is the tip of the iceberg, and there are... 100,000? infections in 8.6 million people, or 1.16%. In a plane of, say, 200 people, assuming (wrongly) that they are independently sampled, there is a 1-(1-1.16%)^200 = 90% chance that any flight contains an infected person. Wow, his statement isn't as ridiculous as it sounded.
Mar 26, 2020 at 2:18 comment added Oddthinking I don't think this answers the question. It just repeats the claim.
Mar 24, 2020 at 22:21 history edited user8356 CC BY-SA 4.0
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Mar 24, 2020 at 19:25 history answered user8356 CC BY-SA 4.0